0.0.1 ↑ 8. Hausaufgabe
0.0.1.1 ↑ Selbstgestellte Aufgabe
{} \begin{array}{rcl} {} f\left(x\right) & = & \left|x\right| - \left|x-1\right| + \left|x-2\right| = \\ {} & = & \begin{cases} {} -x + x-1 - x+2 = -x + 1 & \text{f"ur } x \leq 0; \\ {} +x + x-1 - x+2 = x + 1 & \text{f"ur } 0 < x \leq 1; \\ {} +x - x+1 - x+2 = -x + 3 & \text{f"ur } 1 < x \leq 2; \\ {} +x - x+1 + x-2 = x - 1 & \text{f"ur } x > 2; {} \end{cases} {} \end{array}