0.0.1 ↑ 9. Hausaufgabe
0.0.1.1 ↑ Selbstgestellte Aufgabe
{} \begin{array}{rcl} {} f\left(x\right) & = & 2\cdot\mathrm{sgn}\left(x^2 - 4\right) - \left|x+2\right| = \\ {} & = & \begin{cases} {} 4 + x & \text{f"ur } x < -2; \\ {} 0 & \text{f"ur } x = -2; \\ {} -4 - x & \text{f"ur } -2 < x < 2; \\ {} -4 & \text{f"ur } x = 2; \\ {} -x & \text{f"ur } x > 2; {} \end{cases} {} \end{array}